Mental Ability — Complex Coding-Decoding, Matrix Coding, Conditional Coding
Advanced coding-decoding patterns with 15 solved PSC-pattern problems — matrix coding, conditional coding, symbol coding, and complex letter/number coding.
Advanced coding-decoding patterns with 15 solved PSC-pattern problems — matrix coding, conditional coding, symbol coding, and complex letter/number coding.
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Coding-decoding is one of the most common reasoning topics in Kerala PSC exams. This note covers advanced patterns beyond simple letter shifts, including matrix coding, conditional coding, and mixed coding. 15 solved problems included.
Types of Coding-Decoding
| Type | Description |
|---|---|
| Letter shifting | Each letter replaced by another letter at a fixed distance (e.g., +2: A=C, B=D) |
| Reverse order | Word reversed or letters reversed individually |
| Number coding | Letters replaced by numbers based on a pattern |
| Symbol coding | Letters/words replaced by symbols |
| Mixed coding | Combination of letter shift + reversal + number |
| Matrix coding | Letters encoded using row-column numbers from a matrix/grid |
| Conditional coding | Different rules applied based on conditions (position, vowel/consonant, etc.) |
| Sentence coding | Entire words replaced by codes; determine word-code pairs through comparison |
Pattern 1: Variable Letter Shifting
Instead of a fixed shift, each position has a different shift value.
Rule example: 1st letter +1, 2nd letter +2, 3rd letter +3, and so on.
Problem 1: If COME is coded as DQPH, how is LOVE coded?
Solution:
- Pattern: C(3)+1=D(4), O(15)+2=Q(17), M(13)+3=P(16), E(5)+3=H(8). The shift is +1, +2, +3, +3.
- Applying to LOVE: L(12)+1=M(13), O(15)+2=Q(17), V(22)+3=Y(25), E(5)+3=H(8)
- Answer: MQYH
Problem 2: If BRAND is coded as CSBOE, how is PLANT coded?
Solution:
- B+1=C, R+1=S, A+1=B, N+1=O, D+1=E. Each letter shifted by +1.
- PLANT: P+1=Q, L+1=M, A+1=B, N+1=O, T+1=U
- Answer: QMBOU
Pattern 2: Reverse Alphabet Coding
Each letter replaced by its mirror in the alphabet: A=Z, B=Y, C=X, D=W … (A+Z=27, B+Y=27, etc.)
Formula: Code = 27 - Position
Problem 3: In a certain code, each letter is replaced by its opposite in the alphabet (A=Z, B=Y, C=X…). What is the code for TIGER?
Solution:
- T(20): 27-20=7=G
- I(9): 27-9=18=R
- G(7): 27-7=20=T
- E(5): 27-5=22=V
- R(18): 27-18=9=I
- Answer: GRTVI
Shortcut table for reverse alphabet:
| A=Z | B=Y | C=X | D=W | E=V | F=U | G=T |
|---|---|---|---|---|---|---|
| H=S | I=R | J=Q | K=P | L=O | M=N | N=M |
Pattern 3: Number-Letter Coding
Problem 4: If DELHI is written as 73598, how is HIDE written?
Solution:
- D=7, E=3, L=5, H=9, I=8
- HIDE: H=9, I=8, D=7, E=3
- Answer: 9873
Problem 5: If FACE = 6135 and CAFE = 3165, how is ACE coded?
Solution:
- From FACE: F=6, A=1, C=3, E=5
- From CAFE: C=3, A=1, F=6, E=5 (consistent)
- ACE: A=1, C=3, E=5
- Answer: 135
Pattern 4: Sentence/Word Coding
Problem 6: In a certain code:
- “sky is blue” = “ta pa na”
- “blue is bright” = “na sa pa”
- “sky is clear” = “ta pa ra”
What is the code for “blue”?
Solution:
- Compare sentences 1 and 2: common words “is blue” = common codes “na pa”
- Compare sentences 1 and 3: common words “sky is” = common codes “ta pa”
- From comparison: “is” = “pa” (common to all three)
- From sentence 1 and 2: “blue” = “na” (remaining common code after “is”=“pa”)
- Answer: na
Problem 7: In a certain code:
- “good and bad” = “1 2 3”
- “bad is ugly” = “3 4 5”
- “ugly and good” = “5 2 1”
What is the code for “is”?
Solution:
- “good and bad” = 1 2 3
- “ugly and good” = 5 2 1 (common: “good and” = “1 2”)
- So: good=1, and=2, bad=3
- “bad is ugly” = 3 4 5. bad=3, so is=4 or 5 and ugly=4 or 5
- From “ugly and good” = 5 2 1: ugly=5 (since good=1, and=2)
- Therefore: is=4
- Answer: 4
Pattern 5: Matrix Coding
In matrix coding, two matrices are given. Each letter can be represented by its row-column position.
Matrix 1:
| 0 | 1 | 2 | 3 | 4 | |
|---|---|---|---|---|---|
| 0 | A | B | C | D | E |
| 1 | F | G | H | I | J |
| 2 | K | L | M | N | O |
| 3 | P | Q | R | S | T |
| 4 | U | V | W | X | Y |
A letter is coded as (row, column). So A = 00, B = 01, G = 11, M = 22, Y = 44.
Problem 8: Using the matrix above, how is the word KING coded?
Solution:
- K = row 2, col 0 = 20
- I = row 1, col 3 = 13
- N = row 2, col 3 = 23
- G = row 1, col 1 = 11
- Answer: 20, 13, 23, 11
Problem 9: Using the same matrix, if a word is coded as 30, 24, 13, 23, 34, what is the word?
Solution:
- 30 = row 3, col 0 = P
- 24 = row 2, col 4 = O
- 13 = row 1, col 3 = I
- 23 = row 2, col 3 = N
- 34 = row 3, col 4 = T
- Answer: POINT
Pattern 6: Conditional Coding
Rules change based on conditions (e.g., vowel vs consonant, position in word).
Problem 10: Rules:
- Vowels are coded as the NEXT vowel (A=E, E=I, I=O, O=U, U=A)
- Consonants are coded as the NEXT consonant (B=C, C=D, …, Z=B)
How is BOAT coded?
Solution:
- B (consonant): next consonant = C
- O (vowel): next vowel = U
- A (vowel): next vowel = E
- T (consonant): next consonant = V
- Answer: CUEV
Problem 11: Rules:
- If a letter is at an ODD position in the word: code = letter + 2
- If a letter is at an EVEN position in the word: code = letter - 2
How is LAMP coded?
Solution:
- L (position 1, odd): L+2 = N
- A (position 2, even): A-2 = Y (wrap around: A is the 1st letter, going back 2 positions gives Y, the 25th letter)
- M (position 3, odd): M+2 = O
- P (position 4, even): P-2 = N
- Answer: NYON
Pattern 7: Symbol Substitution Coding
Problem 12: If + means multiply, - means divide, x means add, and / means subtract: What is 8 + 4 - 2 x 6 / 3?
Solution: Replace symbols: + becomes multiply, - becomes divide, x becomes add, / becomes subtract.
- 8 multiply 4 divide 2 add 6 subtract 3
- = (8 x 4) / 2 + 6 - 3
- = 32 / 2 + 6 - 3
- = 16 + 6 - 3
- = 19
Problem 13: If A = 1, B = 2, C = 3 … Z = 26, then what is the code value of KERALA?
Solution:
- K=11, E=5, R=18, A=1, L=12, A=1
- Sum = 11+5+18+1+12+1 = 48
Pattern 8: Mixed Operation Coding
Problem 14: In a coding system:
- First and last letters are swapped
- Middle letters are each shifted by +1
How is DREAM coded?
Solution:
- Original: D R E A M
- Swap first (D) and last (M): M R E A D
- Shift middle letters (R, E, A) by +1: S, F, B
- Result: M S F B D
- Answer: MSFBD
Pattern 9: Clock-Based Coding
Problem 15: In a code, each letter is assigned the number of the hour if we place A-L at positions 1-12 on a clock face (A=1, B=2 … L=12) and then M-X at 1-12 again (M=1, N=2 … X=12), and Y=1, Z=2.
How is MAP coded?
Solution:
- M = 1 (M is 13th letter; 13-12 = 1)
- A = 1
- P = 4 (P is 16th letter; 16-12 = 4)
- Answer: 1, 1, 4
Strategy Tips for PSC Exams
| Tip | Details |
|---|---|
| Check for simple shift first | Try +1, +2, -1, -2 on the first two letters |
| Try reverse alphabet | If shift does not work, check mirror coding (A=Z pattern) |
| Position matters | Note whether the shift varies by position in the word |
| Sentence coding | Find common words between sentences to decode individual words |
| Matrix coding | Simply read row and column; practice reading quickly |
| Verify your answer | Always verify with the given code before choosing |
| Time management | Spend no more than 30-45 seconds per coding question |
PSC Quick Recall
| Pattern | Key Identifier |
|---|---|
| Simple shift | All letters moved by same fixed number |
| Variable shift | Each position has different shift (+1, +2, +3…) |
| Reverse alphabet | A=Z, B=Y, C=X pattern (sum = 27) |
| Sentence coding | Compare overlapping sentences to isolate word codes |
| Matrix coding | Two-digit row-column format |
| Conditional coding | Different rules for vowels vs consonants, or odd vs even positions |
| Symbol substitution | Mathematical operators swapped; solve with BODMAS after substitution |
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